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Home/ Questions/Q 6691845
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:47:58+00:00 2026-05-26T05:47:58+00:00

I wrote the following lines: std::bitset<4> bitvec; //bitset 0000 std::bitset<4> addition; //bitset 0000 addition.set(0);

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I wrote the following lines:

std::bitset<4> bitvec;  //bitset 0000
std::bitset<4> addition; //bitset 0000

addition.set(0); //setting the least significant bit

std::cout << addition << std::endl; //output 0001
std::cout << std::endl;

for(int x = 0; x != 16; ++x) { //addition loop
    std::cout << bitvec << std::endl; //output
    bitvec &= addition; //binary AND
}

std::cout << std::endl;

and I expected the output to be:

0000
0001
0010
0011
0100
0101
....

But the loop just outputs ‘0000’. What basic concept am I missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:47:58+00:00Added an answer on May 26, 2026 at 5:47 am

    Logical AND is not addition.

    Specifically,

      0000
    & 0001
    ------
    = 0000
    

    Which explains why you always get 0000.

    Logical AND just looks at each bit in both bitsets and only outputs a 1 if that bit is 1 in both of the other vectors. As an example:

      1001
    & 1100
    ------
    = 1000
    

    The reason that first bit is 1 is because the first bit in the other bitsets is 1. The rest are 0 because one of the bitsets has a 0 at that position.

    If you want addition, don’t use a bitset, and just use addition.

    unsigned long a = 0;
    
    for (int i = 0; i < 16; ++i)
    {
        std::cout << std::bitset<4>(a) << std::endl;
        ++a;
    }
    

    Output:

    0000
    0001
    0010
    0011
    0100
    0101
    0110
    0111
    1000
    1001
    1010
    1011
    1100
    1101
    1110
    1111
    
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