Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7723355
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T04:25:20+00:00 2026-06-01T04:25:20+00:00

I wrote this code in my viewDidLoad function in my iOS project. lettersLeftLabel.text =

  • 0

I wrote this code in my viewDidLoad function in my iOS project.

lettersLeftLabel.text = @"ABCDEFGH\nIJKLMNOP\nQRSTUVWX\nYZ";

lettersLeftLabel is a text label.

However, no newlines appear. Why?

Also, lettersLeftLabel.text apparently cannot be an integer either:

lettersLeftLabel.text = myIntegerValue;

fails too. How come?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T04:25:21+00:00Added an answer on June 1, 2026 at 4:25 am

    Put your code in viewDidAppear instead.

    Of course you cannot assign a int to a NSString*. To do that you must do something like

    lettersLeftLabel.text = [NSString stringWithFormat:@"%d",myIntegerValue];
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I wrote this code for converting binary to text . public static void main(String
I wrote this code: function get_feed(){ // Get RSS Feed(s) include_once(ABSPATH . WPINC .
I wrote this code to control whether a char[] is null or not. char[]
I wrote this code I have these errors Cannot implicitly convert type x.Program.TreeNode' to
I wrote this code in C# to encrypt a string with a key: private
I wrote this code. The constructor works normally, but in the destructor I get
I wrote this code that compiles on Solaris gcc it works fine too for
I wrote this code: ScheduledExecutorService ExtractorTimer=Executors.newScheduledThreadPool(1); final ScheduledFuture<?> SchedulerHandle; SchedulerHandle =ExtractorTimer.scheduleWithFixedDelay( new Runnable() {
If I wrote this code: typeof(myType).TypeHandle Would it use reflection? How much different from:
Hi guys I wrote this code and i have two errors. Invalid rank specifier:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.