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Home/ Questions/Q 6182597
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:13:34+00:00 2026-05-24T01:13:34+00:00

I wrote this code: <? $text=’how are you [b] today [/b]’; $patterns = array();

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I wrote this code:

<?
$text='how are you [b] today [/b]';
$patterns = array();
$patterns[0] = '/\[b/';
$patterns[1] = '/\b]/';
$replacements = array();
$replacements[1] = 'b]aaa<>';
$replacements[0] = '<>aaa[b';


ksort($patterns);
ksort($replacements);
echo preg_replace($patterns, $replacements, $text);
echo "_";
echo $text;
echo "_";
echo "END";

?>

the output shows:

how are you <>aaa[bb]aaa<> today [/b]aaa<>______how are you [b] today [/b]______END

but the output should be:

how are you <>aaa[b] today [/b]aaa<>______how are you [b] today [/b]______END

what did I do wrong? Please help. Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:13:37+00:00Added an answer on May 24, 2026 at 1:13 am

    You need to double-escape the brackets:

    $patterns[0] = '/\\[b/';
    

    A single backslash will be “consumed” by PHP when it parses the string, leaving just a bare [, which will be seen by the regex engine as the beginning of a character class. By double-escaping, the \\ will be seen by PHP as an escape, leaving a single \, which will be seen by the regex engine as an escape.

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