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Editorial Team
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Asked: 2026-06-09T22:57:36+00:00

iam using 3 different databases for my project. it contain same password and user

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iam using 3 different databases for my project.
it contain same password and user name. the code is

$con = mysql_pconnect(hostname, username, password) or die("Connection     Error: " . mysql_error());
mysql_select_db(database_name, $con) or die("Error connecting to DB. " . mysql_error());

$con1 = mysql_pconnect(hostname, username, password) or die("Connection Error: " . mysql_error());
mysql_select_db(database_name, $con) or die("Error connecting to DB. " . mysql_error());

$con2 = mysql_pconnect(hostname, username, password) or die("Connection Error: " . mysql_error());
mysql_select_db(database_name, $con) or die("Error connecting to DB. " . mysql_error());

three database not connected properly.

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1 Answer

  1. Editorial Team

    It looks like you are possibly missing either $ in front of variables for the connection strings:

    $con = mysql_pconnect($hostname, $username, $password) or die("Connection     Error: " . mysql_error());

    Or you need to be sure tn use quotes around the entries.

    On that note though, you should probably be using PDO to connect to databases if you are writing fresh code.

    Edit: Also, even though you are making new connections, you do keep using the first $con you define in the mysql_select_db statements (all use $con rather than $con1, $con2).

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