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Home/ Questions/Q 330673
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T09:42:11+00:00 2026-05-12T09:42:11+00:00

If I allocate an object in a method, ‘getASprocket’ and call it this way,

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If I allocate an object in a method, ‘getASprocket’ and call it this way, will there be a leak here?

Sprocket *sprock = [Sprocket getASprocket];

// store this returned value as an ivar
ivarSprock = [sprock retain];

// release the originally acquired object
[sprock release];

The Sprocket object is allocated and returned this way:

– (Sprocket *)getASprocket {
    Sprocket *sprocket;

    sprocket = [[Sprocket alloc] init];

    return [sprocket retain];
}

Also, would changing from '[sprocket retain];' inside the ‘aSprocket’ method to 'return [sprocket autorelease];' make worse performance hit?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T09:42:12+00:00Added an answer on May 12, 2026 at 9:42 am

    Please see this good explanation page Especially sub-page #7

    each retain created another memory object. so lets see what we’ve got:

    in getASprocket :

    sprocket = [[Sprocket alloc] init];
    

    +1

    return [sprocket retain];
    

    +1

    and on your method:

    ivarSprock = [sprock retain];
    

    +1

    [sprock release];
    

    -1

    What should we do?
    Well we should let the Sprock go by making it autorelease:

      return [[[Sprocket alloc] init] autorelease]
    

    or in the words of the reffered link above:

    In most cases, the setter for an instance variable should just autorelease the old object, and retain the new one. You then just make sure to release it in dealloc as well.

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