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Home/ Questions/Q 8258297
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T02:29:30+00:00 2026-06-08T02:29:30+00:00

If I do this int wsIdx[length]; I’ve a segFault but if I do this

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If I do this

int wsIdx[length];

I’ve a segFault

but if I do this

int *wsIdx;
wsIdx = (int *)malloc(sizeof(int) * length );

there’s no problem.

This problem appears only when length is high, 2560000 during my tests. I’ve widely enough memory. Could you explain me the differences between the two allocation method, and why the first does not work? Thank you.

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  1. Editorial Team
    Editorial Team
    2026-06-08T02:29:32+00:00Added an answer on June 8, 2026 at 2:29 am

    The first one gets allocated on the “stack” (an area usually used for local variables), while the second one gets allocated on the “heap” an area for dynamically allocated memory.

    You don’t have enough stack space to allocate in the first way, your heap is large.

    This SO discussion might be helpful: What and where are the stack and heap?.

    When you are allocating memory dynamically, you can always check for success or failure of the allocation by examining the return value of malloc/calloc/etc .. no such mechanism exists unfortunately for allocating memory on the stack.

    Aside: You might enjoy reading this in the context of this question, especially this part 🙂

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