Question

If I got this function, fun(t1, t2, t3), and I call it by fun(v1, v2), is it possible to get a default value for v3 though it hasn’t been specified what that would be? Such as bool being false, pointer being null, int being 0 etc. Or should that raise compiler error?

Answer 1

It will raise a compiler error if the function isn’t overloaded.

If you can’t change the prototype, you can overload it yourself:

void fun (bool t1, bool t2)
{ 
   fun (t1,t2, true); //or whatever
}

or if you can change it, you can declare a default for the parameter like this:

void fun (bool t1, bool t2, bool t3 = true)
{ 
}