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Home/ Questions/Q 8230703
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T17:13:25+00:00 2026-06-07T17:13:25+00:00

If I have a class definition class myClass { void x(); }; void myClass::x()

  • 0

If I have a class definition

class myClass
{
  void x(); 
};


void myClass::x()
{
   hello(); // error: ‘hello’ was not declared in this scope
}

void hello()
{
   cout << "Hello\n" << endl;
}

How can I call a function defined outside the scope of a class and located in the same file ? I know that I can use Namespace::function but I am not sure in this case what I should use for Namespace

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T17:13:26+00:00Added an answer on June 7, 2026 at 5:13 pm

    You must at least declare it (if not define it) before its use.

    Usually, this is done in an anonymous namespace if the function’s functionality is only used in that translation unit:

    class myClass
    {
      void x(); 
    };
    
    namespace
    {
       void hello()
       {
          cout << "Hello\n" << endl;
       }
    }
    
    void myClass::x()
    {
       hello(); // error: ‘hello’ was not declared in this scope
    }
    

    This gives the function internal linkage (similar to declaring it static) and is only available in that TU.

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