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Home/ Questions/Q 6819703
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:20:17+00:00 2026-05-26T21:20:17+00:00

If I have a function say: var my_function = function() { } If the

  • 0

If I have a function say:

var my_function = function()
  {
  }

If the function is not called, it is not taking up memory, it is just text sitting in memory.

However if you call it by say…

function_instance = new my_function();

It is instantiated is a sort of way, and the variables and methods it contains are loaded into memory.

Is this a way to represent a class/object model similar to C++?

Is my interpretation correct?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:20:17+00:00Added an answer on May 26, 2026 at 9:20 pm

    “a way to represent a class/object model similar to C++” would be through the use of prototypes.

    As Kevin M pointed out, you can use the this keyword to create instance variables in a function, like so:

    var my_function(foo)
    {
      this.foo = foo;
      this.bar = function()
      {
        // bar-ing here
      }
    }
    

    The problem however, that whenever you instantiate my_function(), a new instance of the my_function.bar function is also created. Enter prototypes:

    var barPrototype = { "bar" : function()
      {
        // bar-ing here
      }
    };
    
    var my_function(foo)
    {
      this.foo = foo;
    }
    my_function.prototype = barPrototype;
    

    So, to sum it all up, the prototype keyword can be used to create function-specific, inheritable properties that are analoguous to C++’s member functions. Member functions of C++ aren’t instantiated for each instance of a class. Instead, the compiler adds a this pointer to the function’s parameters; this pointer points to the instance that the member function is called on.

    More JSey fun to be had here: http://javascript.infogami.com/Javascript_in_Ten_Minutes

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