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Home/ Questions/Q 51493
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Asked: May 10, 20262026-05-10T16:45:32+00:00 2026-05-10T16:45:32+00:00

If I have an array of a fixed size depending on how it is

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If I have an array of a fixed size depending on how it is defined and used, I typically use one of two ways to reference it.

Array type 1: Since it is a fixed size based on a define, I just use that define in all my loops referencing it.

#define MAXPLAYERS 4  int playerscores[MAXPLAYERS];  for(i=0;i<MAXPLAYERS;++i) { .... do something with each player } 

Array type 2: Since this array can grow as items are added to it, I use the sizeof to count the number of entries in it. The size would be converted to a constant by the compiler so there shouldn’t be any runtime penalty to doing it this way.

typedef struct {     fields.... }MYSTRUCT_DEF;  MYSTRUCT_DEF mystruct[]={    {entry 1},    {entry 2},    {entry 3...n}    };   for(i=0;i<(sizeof(mystruct)/sizeof(MYSTRUCT_DEF));++i)  {  ..... do something with each entry  } 

Is there a more elegant solution to handling processing of arrays without going past the end or stopping too early. Thoughts? Comments?

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  1. 2026-05-10T16:45:33+00:00Added an answer on May 10, 2026 at 4:45 pm

    This will work for both of your cases, regardless of array element type:

    #define ARRAY_COUNT(x) (sizeof(x)/sizeof((x)[0]))  ...  struct foo arr[100]; ...  for (i = 0; i < ARRAY_COUNT(arr); ++i) {     /* do stuff to arr[i] */ } 
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