Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 343757
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T10:55:38+00:00 2026-05-12T10:55:38+00:00

If I have the following xml: XDocument xDocument = new XDocument( new XElement(RootElement, new

  • 0

If I have the following xml:

        XDocument xDocument = new XDocument(
            new XElement("RootElement",
                new XElement("ChildElement",
                    new XAttribute("Attribute1", "Hello"),
                    new XAttribute("Attribute2", "World")
                ),
                new XElement("ChildElement",
                    new XAttribute("Attribute1", "Foo"),
                    new XAttribute("Attribute2", "Bar")
                )
            )
        );

I’m after the output “Hello, Foo” using LINQ “.” notation.

I can get “Hello” using

xDocument.Element("RootElement").Element("ChildElement").Attribute("Attribute1").Value;

I can get all of the Attributes using

xDocument.Element("RootElement").Elements("ChildElement").Attributes("Attribute1");

How can I get a list of the string values of the attributes so that I can join then as a comma separated list?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T10:55:38+00:00Added an answer on May 12, 2026 at 10:55 am

    Ok, so thanks to womp I realised it was the Select method I needed in order to obtain the property Value so I could get an array of strings. Therefore, the following works.

    String.Join(",", (string[]) xDocument.Element("RootElement").Elements("ChildElement").Attributes("Attribute1").Select(attribute => attribute.Value).ToArray());
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following: XDocument xdoc = XDocument.Load(C:\\myfile.xml); List<Tag> list = new List<Tag>(); foreach
I have the following XML document: <projects> <project> <name>Shockwave</name> <language>Ruby</language> <owner>Brian May</owner> <state>New</state> <startDate>31/10/2008
I have the following XML LINQ query from my XDocument. var totals = (from
I have the following xml in an XDocument (confirmed by checking in the debugger)
I have the following XML Document (that can be redesigned if necessary) that stores
In Flex, I have an xml document such as the following: var xml:XML =
I have an XML document with a section similar to the following: <release_list> <release>
I have an xml document which consists of a number of the following: -
I have an XML document which contains nodes like following:- <a class=custom>test</a> <a class=xyz></a>
I have a simple xml document that looks like the following snippet. I need

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.