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Home/ Questions/Q 4084232
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:24:49+00:00 2026-05-20T18:24:49+00:00

If I have these two rows: Users Table UserId | Username | Etc… 5

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If I have these two rows:

Users Table      UserId  |  Username  |  Etc...
                 5       |  John      |

Avatars Table    Id      |  UserId    |  ImageName         |  ImageType
                 1       |  5         |  example.png       |  original
                 2       |  5         |  example_thumb.png |  thumbnail

And I have:

SELECT * FROM Users JOIN Avatars 
ON Users.UserId=Avatars.UserId WHERE Users.UserId = '5'

Do I have to add the additional:

AND Avatars.ImageType = 'thumbnail'

Or is there a way to select all and get the one I want with php (much like an array: $var[‘something’])??

Or is it possible to distinguish them with mysql using something like the ‘AS’ clause??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:24:49+00:00Added an answer on May 20, 2026 at 6:24 pm

    Without further qualifying the join with the ImageType condition, you will get multiple rows per user record.

    Edit: For example

    SELECT u.UserId, u.Username, a.ImageName, a.ImageType
    FROM Users u
    INNER JOIN Avatars a ON u.UserId = a.UserId
    WHERE u.UserId = 5
    
    UserId    Username    ImageName            ImageType
    ----------------------------------------------------
    5         John        example.png          original
    5         John        example_thumb.png    thumbnail
    

    Edit #2: If you want both images in one row, use this query

    SELECT u.UserId, u.Username,
        orig.ImageName as OriginalImage, thumb.ImageName as ThumbImage
    FROM Users u
    INNER JOIN Avatars orig ON u.UserId = orig.UserId
        AND orig.ImageType = 'original'
    INNER JOIN Avatars thumb ON u.UserId = thumb.UserId
        AND thumb.ImageType = 'thumbnail'
    WHERE u.UserId = 5
    

    Note that this will only return rows where both image types are present for the user in Avatars. If you want to get a result irrespective of the existence of avatar images, use left joins.

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