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Home/ Questions/Q 648113
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:47:49+00:00 2026-05-13T21:47:49+00:00

if(strpos(http://www.example.com,http://www.)==0){ // do work} I’d expect this to resolve as true, which it does.

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if(strpos("http://www.example.com","http://www.")==0){ // do work}

I’d expect this to resolve as true, which it does. But what happens when I do

if(strpos("abcdefghijklmnop","http://www.")==0){// do work}

This also passes on php 5 because as far as I can work out the strpos returns false which translates as 0.

Is this correct thinking/behaviour? If so what is the workaround for testing for that a substring is at the beginning of another string?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:47:49+00:00Added an answer on May 13, 2026 at 9:47 pm

    Yes, this is correct / expected behavior :

    • strpos can return 0 when there is a match at the beginning of the string
    • and it will return false when there is no match

    The thing is you should not use == to compare 0 and false ; you should use ===, like this :

    if(strpos("abcdefghijklmnop","http://www.") === 0) {
    
    }
    

    Or :

    if(strpos("abcdefghijklmnop","http://www.") === false) {
    
    }
    

    For more informations, see Comparison Operators :

    • $a == $b will be TRUE if $a is equal to $b.
    • $a === $b will be TRUE if $a is equal to $b, and they are of the same type.

    And, quoting the manual page of strpos :

    This function may return Boolean
    FALSE, but may also return a
    non-Boolean value which evaluates to
    FALSE, such as 0 or "".
    Please
    read the section on Booleans for
    more information.
    Use the ===
    operator
    for testing the return
    value of this function.

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