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Editorial Team
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Asked: 2026-05-28T05:29:27+00:00

if(typeid(int) == typeid(const int)) cout << Same types<< endl; PROGRAM OUTPUT: Same types am

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if(typeid(int) == typeid(const int))
       cout << "Same types"<< endl;

PROGRAM OUTPUT:

Same types

am I missing something?
these are not same types lol.

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1 Answer

  1. Editorial Team

    They aren’t the same type, but the typeid operator strips const and volatile.

    From section 5.2.8 [expr.typeid]:

    The top-level cv-qualifiers of the glvalue expression or the type-id that is the operand of typeid are always ignored.

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