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Home/ Questions/Q 771651
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:41:12+00:00 2026-05-14T18:41:12+00:00

I’m just reading about Prototypes in JavaScript and Douglas Crockford offers and excellent way

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I’m just reading about Prototypes in JavaScript and Douglas Crockford offers and excellent way to select a new objects prototype but can anyone explain (below) why obj01’s type equals ‘object’ when I pass it in function as it’s prototype?

if (typeof Object.beget !== 'function') {
     Object.beget = function (o) {
         console.log(typeof o);//function
         var F = function () {};
         F.prototype = o;
         console.log(typeof F);//function
         return new F();
     };
}
var func01 = function(){};
var obj01 = Object.beget(func01);
console.log(typeof obj01);//object
console.log(typeof obj01.prototype);//object

I thought it would be

console.log(typeof obj01);//function
console.log(typeof obj01.prototype);//function
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  1. Editorial Team
    Editorial Team
    2026-05-14T18:41:13+00:00Added an answer on May 14, 2026 at 6:41 pm

    obj01 is simply an object that inherits from a function object, you can’t create functions in this way.

    The typeof operator returns "function" only when its operand is by itself callable.

    There are only three valid ways to create function objects:

    Function declaration:

    function name (/*arg, argn...*/) {
    }
    

    Function expression:

    var fn = function /*nameopt*/ (/*arg, argn...*/) {
    };
    

    Function constructor:

    var fn = new Function("arg", "argn", "FunctionBody");
    

    Edit: In response to your comment, obj01 , is just an object, its prototype chain contains a function object, then Function.prototype and then Object.prototype but that doesn’t make an object callable.

    Your object is not callable, functions are just objects, but they have some special internal properties that allow them to behave like that.

    An object is callable only if it implements the internal [[Call]] property.

    There are other internal properties that function objects have, like the [[Construct]], which is invoked when the new operator is used, the [[Scope]] property which stores the lexical environment where the function is executed, and more.

    If you try to invoke your object like if it were a function, you will have a TypeError, because when you make a function call, the object needs to have the [[Call]] internal property.

    Function objects need to have the above internal properties, and the only way that they can be constructed is by the three methods I mentioned early, you can see how internally functions objects are created here.

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