Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 771651
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T18:41:12+00:00 2026-05-14T18:41:12+00:00

I’m just reading about Prototypes in JavaScript and Douglas Crockford offers and excellent way

  • 0

I’m just reading about Prototypes in JavaScript and Douglas Crockford offers and excellent way to select a new objects prototype but can anyone explain (below) why obj01’s type equals ‘object’ when I pass it in function as it’s prototype?

if (typeof Object.beget !== 'function') {
     Object.beget = function (o) {
         console.log(typeof o);//function
         var F = function () {};
         F.prototype = o;
         console.log(typeof F);//function
         return new F();
     };
}
var func01 = function(){};
var obj01 = Object.beget(func01);
console.log(typeof obj01);//object
console.log(typeof obj01.prototype);//object

I thought it would be

console.log(typeof obj01);//function
console.log(typeof obj01.prototype);//function
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T18:41:13+00:00Added an answer on May 14, 2026 at 6:41 pm

    obj01 is simply an object that inherits from a function object, you can’t create functions in this way.

    The typeof operator returns "function" only when its operand is by itself callable.

    There are only three valid ways to create function objects:

    Function declaration:

    function name (/*arg, argn...*/) {
    }
    

    Function expression:

    var fn = function /*nameopt*/ (/*arg, argn...*/) {
    };
    

    Function constructor:

    var fn = new Function("arg", "argn", "FunctionBody");
    

    Edit: In response to your comment, obj01 , is just an object, its prototype chain contains a function object, then Function.prototype and then Object.prototype but that doesn’t make an object callable.

    Your object is not callable, functions are just objects, but they have some special internal properties that allow them to behave like that.

    An object is callable only if it implements the internal [[Call]] property.

    There are other internal properties that function objects have, like the [[Construct]], which is invoked when the new operator is used, the [[Scope]] property which stores the lexical environment where the function is executed, and more.

    If you try to invoke your object like if it were a function, you will have a TypeError, because when you make a function call, the object needs to have the [[Call]] internal property.

    Function objects need to have the above internal properties, and the only way that they can be constructed is by the three methods I mentioned early, you can see how internally functions objects are created here.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am reading a book about Javascript and jQuery and using one of the
I have just tried to save a simple *.rtf file with some websites and
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I used javascript for loading a picture on my website depending on which small
I have a small JavaScript validation script that validates inputs based on Regex. I
I want use html5's new tag to play a wav file (currently only supported
I am trying to render a haml file in a javascript response like so:
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I'm trying to select an H1 element which is the second-child in its group

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.