I’m running through an XML document, selecting all the elements, and creating links based on the ancestor which is usually two nodes up in the tree, but occasionally 3 or 4 nodes up. For the majority of the elements, using <xsl:value-of select='translate(../../@name,$uc,$lc)' /> works just fine, but for the cases where the ancestor is 3 or so nodes up, I’d like to use <xsl:value-of select='translate(ancestor::package/@name,$uc,$lc)' />, but this doesn’t work.
I’m using xsltproc from Ruby to do my XSL transforms.
Sample tree (yes, it has XSLT in it, no, I’m not trying to process it):
<package name='blork!' xmlns='http://xml.snapin.com/XBL'> <xsl:template name='doSomething'> <tokens> <token name='text-from-resource' export='public' /> </tokens> </xsl:template> </package> The XSL I’m using:
<xsl:stylesheet version='1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform' xmlns:s4='http://xml.snapin.com/XBL'> <xsl:template match='/'> <xsl:if test='count(//s4:token) >0'> <xsl:text>Tokens!</xsl:text> <xsl:for-each select='//s4:token'> <xsl:choose> <xsl:when test='@export='global'' /> <xsl:otherwise> <xsl:value-of select='translate(ancestor::s4:package/@name,$uc,$lc)' /> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:if> </xsl:template> </xsl:stylesheet> Edit: Ah, right, forgot the namespace on the select. The parser’s finding that ancestor properly for most cases, but it still can’t find it when there’s an xsl: node in there, and the target file has no namespace for xsl. I’d prefer not to modify the target file, because it’s production code—I’m just writing an autodoc tool.
Your problem is probably namespace related. You haven’t included those in the sample tree – can you be a bit more precise in what you’ve pasted? Assuming the package node is in the same namespace as the token node, try:
You can also test just the unqualified name, though it will be slower:
W3C local-name() spec here.