I’m trying to overload the operator << as a friend to a template class Pair, but I keep getting a compiler warning saying
friend declaration std::ostream& operator<<(ostream& out, Pair<T,U>& v) declares a non template function
for this code:
friend ostream& operator<<(ostream&, Pair<T,U>&);
it gives a second warning as a recommendation saying
if this is not what you intended, make sure the function template has already been declared and add <> after the function name here
Here is the function definition
template <class T, class U>
ostream& operator<<(ostream& out, Pair<T,U>& v)
{
out << v.val1 << " " << v.val2;
}
and here is the whole class.
template <class T, class U>
class Pair{
public:
Pair(T v1, U v2) : val1(v1), val2(v2){}
~Pair(){}
Pair& operator=(const Pair&);
friend ostream& operator<<(ostream&, Pair<T,U>&);
private:
T val1;
U val2;
};
I wasn’t sure what to draw from the recommendation warning, other than that maybe I have to put somewhere in the friend declaration. Does anyone know the proper syntax for this? Thanks.
You declare operator<< as returning an ostream&, but there is no return statement at all in the method. Should be:
Other than that, I have no problems or warnings compiling your code under Visual Studio 2008 with warnings at level 4. Oh, there are the classical linker errors, but that is easily bypassed by moving the template function definition to the class declaration, as explained in the C++ FAQ.
My test code: