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Home/ Questions/Q 7769745
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T16:14:03+00:00 2026-06-01T16:14:03+00:00

I’m trying to understand what the best practice is and why for concatenating string

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I’m trying to understand what the best practice is and why for concatenating string literals and variables for different cases. For instance, if I have code like this

StringBuilder sb = new StringBuilder("AAAAAAAAAAAAA")
    .append(B_String).append("CCCCCCCCCCC").append(D_String)
    .append("EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE")
    .append("FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF");

Is this the way to do it? From this post, I noticed that the + operator on Strings creates a new instance of StringBuilder, concatenates the operands, and returns a String conversion, which seems like a lot more work than just calling .append(); so if that’s true, then that is out of the question. But what about String.concat()? Is it proper to use .append() for every concatenation? Or just for variables, and literals are okay to append with .concat()?

StringBuilder sb = new StringBuilder("AAAAAAAAAAAAA")
    .append(B_String.concat("CCCCCCCCCCC")).append(D_String
    .concat("EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE")
    .concat("FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF"));

What are the general rules for best practices and performance for going about these situations? Is my assumption correct on + and it should really just not be used?

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  1. Editorial Team
    Editorial Team
    2026-06-01T16:14:04+00:00Added an answer on June 1, 2026 at 4:14 pm

    + operator

    String s = s1 + s2
    

    Behind the scenes this is translated to:

    String s = new StringBuilder(s1).append(s2).toString();
    

    Imagine how much extra work it adds if you have s1 + s2 here:

    stringBuilder.append(s1 + s2)
    

    instead of:

    stringBuilder.append(s1).append(s2)
    

    Multiple strings with +

    Worth to note that:

    String s = s1 + s2 + s3 + ... +sN
    

    is translated to:

    String s = new StringBuilder(s1).append(s2).append(s3)...apend(sN).toString();
    

    concat()

    String s = s1.concat(s2);
    

    String creates char[] array that can fit both s1 and s2. Copies s1 and s2 contents to this new array. Actually requires less work then + operator.

    StringBuilder.append()

    Maintains an internal char[] array that grows when needed. No extra char[] is created if the internal one is sufficiently big.

    stringBuilder.append(s1.concat(s2))
    

    is also performing poorly because s1.concat(s2) creates an extra char[] array and copies s1 and s2 to it just to copy that new array contents to internal StringBuilder char[].

    That being said you should use append() all the time and append raw strings (your first code snippet is correct).

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