I’m writing code to recursively replace predefined variables from inside a given string. The variables are prefixed with the character ‘%’. Input strings that start with ‘^’ are to be evaluated.
For instance, assuming an array of variables such as:
$vars['a'] = 'This is a string';
$vars['b'] = '123';
$vars['d'] = '%c'; // Note that $vars['c'] has not been defined
$vars['e'] = '^5 + %d';
$vars['f'] = '^11 + %e + %b*2';
$vars['g'] = '^date(\'l\')';
$vars['h'] = 'Today is %g.';
$vars['input_digits'] = '*****';
$vars['code'] = '%input_digits';
The following code would result in:
a) $str = '^1 + %c';
$rc = _expand_variables($str, $vars);
// Result: $rc == 1
b) $str = '^%a != NULL';
$rc = _expand_variables($str, $vars);
// Result: $rc == 1
c) $str = '^3+%f + 3';
$rc = _expand_variables($str, $vars);
// Result: $rc == 262
d) $str = '%h';
$rc = _expand_variables($str, $vars);
// Result: $rc == 'Today is Monday'
e) $str = 'Your code is: %code';
$rc = _expand_variables($str, $vars);
// Result: $rc == 'Your code is: *****'
Any suggestions on how to do that? I’ve spent many days trying to do this, but only achieved partial success. Unfortunately, my last attempt managed to generate a ‘segmentation fault’!!
Help would be much appreciated!
Note that there is no check against circular inclusion, which would simply lead to an infinite loop. (Example:
$vars['s'] = '%s';..) So make sure your data is free of such constructs.The commented code
can be used or skipped. If it is skipped, any replacement is quoted, if the string
$strwill be evaluated later on! But since PHP automatically converts strings to numbers (or should I say it tries to do so??) skipping the code should not lead to any problems.Note that boolean values are not supported! (Also there is no automatic conversion done by PHP, that converts strings like ‘true’ or ‘false’ to the appropriate boolean values!)
The above code assumes PHP 5.3 since it uses a closure.
Output:
For PHP < 5.3 the following adapted code can be used: