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Home/ Questions/Q 7002007
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:52:29+00:00 2026-05-27T20:52:29+00:00

Imagine the following code, written in C#: public class Provider<T> { T GetValue(); //

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Imagine the following code, written in C#:

public class Provider<T>
{
   T GetValue();  // implementation skipped for brevity
}

//

public class Converter<T1, T2>
{
    T2 Convert(T1 value);// implementation skipped for brevity
}

//

public class SomeClass // No Generics Here
{

    public T2 DoSomething<T1, T2>()
    {
        T1 value = new Provider<T1>().GetValue();
        T2 result = new Converter<T1, T2>().Convert(value);

        return result;
    }
}

// and the usage
...
SomeClass some = new SomeClass();
SomeOtherType result = some.DoSomething<SomeType, SomeOtherType>();

Is it possible to achieve the same with Java – I want to know how to call a method in Java by providing the type arguments in the method usage, like above. I’ve done this in .NET and I know Java supports type constraints and inference, I am just messing it up with the syntax.

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:52:30+00:00Added an answer on May 27, 2026 at 8:52 pm

    Both Provider and Converter are fine as they are, your DoSomething method should be re-written like so:

    public <T1, T2> T2 doSomething() {
      T1 value = new Provider<T1>().GetValue();
      T2 result = new Converter<T1, T2>().Convert(value);
      return result;
    }
    

    Which is useable like so:

    SomeClass instance = new SomeClass();
    Integer something = instance.<String, Integer>doSomething();
    
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