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Home/ Questions/Q 9061331
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T15:27:25+00:00 2026-06-16T15:27:25+00:00

import urllib import lxml.html down=’http://blog.sina.com.cn/s/blog_71f3890901017hof.html’ file=urllib.urlopen(down).read() root=lxml.html.document_fromstring(file) body=root.xpath(‘//div[@class=articalContent ]’)[0] print body.text_content() When i run

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import urllib
import lxml.html
down='http://blog.sina.com.cn/s/blog_71f3890901017hof.html'
file=urllib.urlopen(down).read()
root=lxml.html.document_fromstring(file)
body=root.xpath('//div[@class="articalContent  "]')[0]
print body.text_content()

When i run the code, what i get is the text content ,how can i get the html source code of it,not the text content?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T15:27:27+00:00Added an answer on June 16, 2026 at 3:27 pm

    Use

    html = lxml.html.tostring(node)
    

    and please: read the basic documentation of the tools you are using first.

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