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Home/ Questions/Q 8027289
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T23:45:54+00:00 2026-06-04T23:45:54+00:00

In a given shell, normally I’d set a variable or variables and then run

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In a given shell, normally I’d set a variable or variables and then run a command. Recently I learned about the concept of prepending a variable definition to a command:

FOO=bar somecommand someargs

This works… kind of. It doesn’t work when you’re changing a LC_* variable (which seems to affect the command, but not its arguments, for example, [a-z] char ranges) or when piping output to another command thusly:

FOO=bar somecommand someargs | somecommand2  # somecommand2 is unaware of FOO

I can prepend somecommand2 with FOO=bar as well, which works, but which adds unwanted duplication, and it doesn’t help with arguments that are interpreted depending on the variable (for example, [a-z]).

So, what’s a good way to do this on a single line?

I’m thinking something on the order of:

FOO=bar (somecommand someargs | somecommand2)  # Doesn't actually work

I got lots of good answers! The goal is to keep this a one-liner, preferably without using export. The method using a call to Bash was best overall, though the parenthetical version with export in it was a little more compact. The method of using redirection rather than a pipe is interesting as well.

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  1. Editorial Team
    Editorial Team
    2026-06-04T23:45:55+00:00Added an answer on June 4, 2026 at 11:45 pm
    FOO=bar bash -c 'somecommand someargs | somecommand2'
    
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