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Home/ Questions/Q 296565
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:33:36+00:00 2026-05-12T06:33:36+00:00

In BASH, I want to do something like this: #!/bin/bash HOST=blah USER=foo REMOTE_ROOT=${HOST}:~${USER}/ REP_NAME=`basename

  • 0

In BASH, I want to do something like this:

#!/bin/bash                                                                     

HOST="blah"
USER="foo"
REMOTE_ROOT="${HOST}:~${USER}/"

REP_NAME=`basename $1`
TARGET_NAME="${REP_NAME}.git"

CMD1="git clone --bare $1 $TARGET_NAME"
CMD2="touch ${TARGET_NAME}/git-daemon-export-ok"
CMD3="scp -r $TARGET_NAME $REMOTE_ROOT"
CMD4="rm -rf $TARGET_NAME"

for i in {1..4}
do
  CMD="${CMD${i}}"
  echo "$CMD"
  `$CMD`
done

That is to say, I want to loop over a list of commands, display the command being executed, then execute it.

I don’t know how to do the double dereferencing (CMD=”${CMD${i}}” isn’t legal in BASH).

Alternately, I’d be happy to do something like:

for CMD in "CMD1 CMD2 CMD3 CMD4"
do
  echo $$CMD
done

but of course that isn’t the right syntax, either.

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  1. Editorial Team
    Editorial Team
    2026-05-12T06:33:37+00:00Added an answer on May 12, 2026 at 6:33 am
    CMDS[1]="git clone --bare $1 $TARGET_NAME"
    CMDS[2]="touch ${TARGET_NAME}/git-daemon-export-ok"
    CMDS[3]="scp -r $TARGET_NAME $REMOTE_ROOT"
    CMDS[4]="rm -rf $TARGET_NAME"
    
    # ...
    
    for x in 1 2 3 4
    do
        ${CMDS[x]};
    done
    
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