Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1012653
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T09:58:43+00:00 2026-05-16T09:58:43+00:00

In C++, when a method is declared, I’ve noticed that sometime the method may

  • 0

In C++, when a method is declared, I’ve noticed that sometime the method may have an assignement appended to it.

Could anyone tell me what this is?

For example:

virtual void MyMethod () = 0;

What doe the ‘= 0’ mean. 🙂

Thanks everyone !!!

  • 1 1 Answer
  • 2 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T09:58:44+00:00Added an answer on May 16, 2026 at 9:58 am

    It means it’s a pure virtual function, i.e. no actual definition of it is available in this class and it must be overridden in a subclass. It’s not actually an assignment as such, zero is the only value you can “assign”.

    And this is C++ syntax; in C# the same would be accomplished with the abstract keyword.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

If I have a method declared like this: private void someFunction(object[] param1) When I
I have a RESTful WCF service with a method declared like this: [OperationContract(Name =
I would like to have a sealed trait which have a declared method that
I have an extension method declared in this way: public static IEnumerable<TEntity> AsEnumerable<TEntity>(this IDBQueryable<TEntity>
I have the following template method declared in my interface: class IObjectFactory { public:
I have class1.m . I declared a method and written in it. Now i
I realize that the method run() must be declared because its declared in the
I have an abstract method in a base class declared like so... public abstract
When different threads access a static method, are objects declared in that method local
I have a method declared on an interface like so: public interface IInterface {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.