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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:54:24+00:00 2026-05-13T09:54:24+00:00

In Javascript, how do I tell if a user is pressing two keys at

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In Javascript, how do I tell if a user is pressing two keys at the same time?

For example, I have drawn a circle in the middle of the screen. I want to move it up while the user holds down the up arrow and right while the user holds down the right arrow. That part works easy. If user holds both the up and right arrows, I want to move the circle diagonally, up and to the right.

It doesn’t look like this possible with basic Javascript event handling, but surely someone has figured out a work around/hack/improvement.

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:54:24+00:00Added an answer on May 13, 2026 at 9:54 am

    Here is what you need to do conceptually (I guess this is called pseudo code):

    Start with something like this:

    var PIXEL_DELTA  = 10; // Distance to move in pixels
    
    var leftPressed  = 0,
        upPressed    = 0,
        downPressed  = 0,
        rightPressed = 0;
    

    Then on every keydown event, test if it the key pressed is left, up, etc and turn its variable from 0 to PIXEL_DELTA.

    On every keyup event, run the same test and turn the correct variable back to 0.

    Then, in your moving code (real code): (This code adapted from Crescent Fresh’s awesome example):

    function move() {
      var dot = document.getElementById('dot'),
          deltaX = rightPressed - leftPressed,
          deltaY = downPressed - upPressed;
    
      if(deltaX) {
        dot.style.left = (parseInt(dot.style.left, 10) || 0) + deltaX + 'px';
      }
    
      if (deltaY) {
        dot.style.top = (parseInt(dot.style.top, 10) || 0) + deltaY + 'px';
      }
    }
    

    The browser will (should) fire a separate keydown/keyup event for each key, even if they are “simultaneously” pressed.

    Working Example

    Crescent Fresh put together a full example on JSBin. Be sure to visit the editable version as well to play with the code.

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