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Home/ Questions/Q 7588341
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:53:54+00:00 2026-05-30T19:53:54+00:00

in my entity i have set this public function setExpiry(\DateTime $expiry = null) {

  • 0

in my entity i have set this

public function setExpiry(\DateTime $expiry = null)
    {
        $this->expiry = $expiry;
    }

in formType i have set this

$builder->add('expiry', 'choice', array(
            'choices'   => array(
date ("Y-m-d H:i:s",mktime(date('H'),date('i'),date('s'),date('m'),date('d')
+3,date('Y'))) => '3 days',

            ));

but when submit, return this error

::setExpiry() must be an instance of DateTime, string given,

i have understand that “string given” but how i can convert in
datatime object?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:53:55+00:00Added an answer on May 30, 2026 at 7:53 pm

    How about something like this:

    new DateTime('@'.strtotime("+3 day")) => '3 days'
    
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