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Home/ Questions/Q 138597
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Asked: May 11, 20262026-05-11T07:17:21+00:00 2026-05-11T07:17:21+00:00

In my project we have a base exception. For handling showing error dialogs, log

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In my project we have a base exception. For handling showing error dialogs, log and such. Im looking for a way to handle all derived classes of that exception, I thought this would work:

try {   main_loop(); } catch (const MyExceptionBase* e) {   handle_error(e); } 

As every child instance thrown could be represented by a pointer to its parent. But no, when exceptions are thrown now, its an unhandled exception.

Why is this? Do c++ only throw exceptions as references? Thereby rendering my catch block useless? But then why does this even compile in the first place?

The only other way I can think of is this:

try {   main_loop(); } catch (const ExceptionA& e) {   handle_error(e); } catch (const ExceptionB& e) {   handle_error(e); } catch (const ExceptionC& e) {   handle_error(e); } 

Which seems kinda ugly. What is the correct way to do this? Dont have a base exception class? Or can it be solved in the way I want?

Ps: What handle_error() does is simply make use of the base class function display_message_box() and cleanly shutdown the program.

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  1. 2026-05-11T07:17:22+00:00Added an answer on May 11, 2026 at 7:17 am

    Just mix the two approaches: use the base class, and use a reference.

    try {   main_loop(); } catch (const MyExceptionBase& e) {   handle_error(e); } 

    BTW C++ can catch pointers, if you throw them. It’s not advisable though.

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