Question

In python except block, I want to print the error message but I don’t want the program to stop executing, I understand that I have to do something like this

try:
    1/0
except: 
    print errorMessage

In the except part, I am looking to put something like java’s printStackTrace()

Answer 1

Take a look at traceback.print_exc() and the rest of the traceback module.

import traceback

try:
    1/0
except:
    print '>>> traceback <<<'
    traceback.print_exc()
    print '>>> end of traceback <<<'

There are some more examples towards the end of the traceback documentation page.