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Home/ Questions/Q 6050473
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:41:31+00:00 2026-05-23T07:41:31+00:00

In the below example, new Thread() doesnt have any reference. Is it possible that

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In the below example, new Thread() doesnt have any reference. Is it possible that it be garbage collected below it is dead ?
Also without extending Thread class or implementing runnable, how are we creating a thread ?

public class TestFive {
    private int x;
    public void foo() {
            int current = x;
            x = current + 1;
    }
    public void go() {
            for(int i = 0; i < 5; i++) {
                    new Thread() {
                            public void run() {
                                    foo();
                                    System.out.print(x + ", ");
                            } 
                    }.start();
            } 
    }
    public static void main(String args[]){
            TestFive bb = new TestFive();
            bb.go();
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-23T07:41:32+00:00Added an answer on May 23, 2026 at 7:41 am

    A new thread that has not been started will be garbage collected when it becomes unreachable in the normal way.

    A new thread that has been started becomes a garbage collection “root”. It won’t be garbage collected until (after) it finishes.

    In the below example, new Thread() doesnt have any reference. Is it possible that it be garbage collected below it is dead ?

    No. It has been started, and hence won’t be garbage collected until it finishes / dies. And it does have a reachable reference until (at least) the point at which the start() call returns.

    Also without extending Thread class or implementing runnable, how are we creating a thread?

    In your example, you have created anonymous subclass of Thread; i.e. a class that extends Thread.

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