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Home/ Questions/Q 6473423
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:27:53+00:00 2026-05-25T06:27:53+00:00

In the code below // Assume there are non-null string arrays arrayA and arrayB

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In the code below

    // Assume there are non-null string arrays arrayA and arrayB 

    // Code 1
    ArrayList<String[]> al = new ArrayList<String[]>();
    String[] tmpStr = new String[2];
    for (int ii = 0; ii < arrayA.length; ii++) {
            tmpStr[0] = arrayA[ii];
            tmpStr[1] = arrayB[ii];
            al.add(ii, tmpStr);
    }

    // Code 2
    ArrayList<String[]> al = new ArrayList<String[]>();

    for (int ii = 0; ii < arrayA.length; ii++) {
            String[] tmpStr = new String[2];
            tmpStr[0] = arrayA[ii];
            tmpStr[1] = arrayB[ii];
            al.add(ii, tmpStr);
    }

Code 2 gives the wanted results — that is, al now contains {arrayA(ii), arrayB(ii)} for each of its index. In code 1, however, al contains {arrayA(last_index), arrayB(last_index)} for all of its indices. Why is that?

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:27:54+00:00Added an answer on May 25, 2026 at 6:27 am

    In the first code block, you declare the string array with size of 2. So it’s defined in memory at once and in the loop you assign the values to that reference so on each loop step, its value is changed and it’ll be added into the ArrayList object.

    I the second code block, inside the loop you initialize the string array, so every time it will create new array object in memory and all the objects will have different references with different values added to them, that will be passed on to the ArrayList object.

    That’s why you get the different values here.

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