Question

In the code below I firstly try to print the ‘normal’ way. Secondly I try to anonymize my function and assign it to a variable which I then print. In Chrome this now proceeds to print the source code. What am I doing wrong?

function sumSq() {
    var  sum = 0;
    for (i=0;i<=10;i++) {
        sum+=i*i;
    }
    return sum;
}
console.log(sumSq());

var mySum = function() {
    var  sum = 0;
    for (i=0;i<=10;i++) {
        sum+=i*i;
    }
    return sum;
}
console.log(mySum);

Answer 1

Call mySum using ():

console.log(mySum());

Functions are objects, so when you call

console.log(mySum);

JS calls toString on the mySum object (which mySum inherits from the Object prototype). That’s why the source gets printed.