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Home/ Questions/Q 851347
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:24:58+00:00 2026-05-15T07:24:58+00:00

In the code below, I’ve added two lines that print output. The first line

  • 0

In the code below, I’ve added two lines that print output. The first line prints junk as usual, but surprisingly the second one gives me a compilation error. Why?

class Student {

  private String name;

  public Student(String name){
         this.name = name;
  }
  public String getName(){
         return name;
  }
}

class StudentServer {

   public StudentServer(){

          Student[] s = new Student[30];
          s[0] = new Student("Nick");

          // LINE 01: This compiles, although prints junk
          System.out.println(s[0]); 

          // LINE 02: I get a error called cannot find symbol
          System.out.println(s[0].getName());
   }

  public static void main(){
         new StudentServer();
  }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:24:58+00:00Added an answer on May 15, 2026 at 7:24 am

    The issue with main method not being a proper application entry point aside, this code should compile and run just fine. The problem seems to lie elsewhere, and there’s not enough information at the moment to identify the source.

    Related questions

    • Java Beginner question about String[] args in the main method
    • Exception in thread “main” java.lang.NoSuchMethodError: main

    On toString()

    The reason why printing s[0] “prints junk as usual” is because you didn’t @Override the toString() method inherited from Object.

    If you had just added this method:

    @Override public String toString() {
       return "Student : " + name;
    }
    

    then printing s[0] wouldn’t print “junk”; it would print whatever the above toString() returns (which in this case, is something reasonably “not junk”).

    Related questions

    • toString() in Java
    • Is toString() only useful for debugging?
    • when to use toString() method
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