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Home/ Questions/Q 8860571
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:17:18+00:00 2026-06-14T15:17:18+00:00

In the following code, why does instanceof return false for both Shape and Rectangle?

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In the following code, why does instanceof return false for both Shape and Rectangle? Also why do the own properties of rec include both x and y from the superclass?

    function Shape(x, y) {
        this.x=x;
        this.y=y;
    }
    Shape.prototype.move = function (x, y) {
        this.x += x;
        this.y += y;
        console.log("x = " + this.x + " y = " + this.y);
    };
    function Rectangle(x, y, w, h) {
        Shape.call(this, x, y);
        this.w = w;
        this.h = h;
    }
    Rectangle.prototype = Object.create(Shape.prototype);
    Rectangle.prototype.area = function() {
        return this.w * this.h;
    };
    var rec = new Rectangle(0,0,10,10);
    console.log("instanceof = " + rec instanceof Shape);
    console.log("instanceof = " + rec instanceof Rectangle);
    rec.move(2,3);
    console.log("area = " + rec.area());
    console.log(Object.getOwnPropertyNames(rec));
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  1. Editorial Team
    Editorial Team
    2026-06-14T15:17:19+00:00Added an answer on June 14, 2026 at 3:17 pm

    Because + is evaluated before instanceof. So you’re asking if:

    "instanceof = " + rec
    

    …a String, is an instanceof your constructors, which it won’t be.

    Either add parenthesis to force the order:

    console.log("instanceof = " + (rec instanceof Shape));
    

    Or, since console.log accepts any number of arguments, pass it as its own:

    console.log("instanceof = ", rec instanceof Shape);
    
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