Question

In the following example a reference to reason is stored in both parent and child. I’d like to avoid this and store the reference only in parent (usual use of Java exceptions).

import java.lang.{Exception, Throwable}
class FileError(message: String, reason:Throwable) extends Exception(message, reason) {
  ...
}

How do I initialize a parent class field without storing a value in the child class object?

Answer 1

If you never use reason in the FieldError class, then it will not be stored in FieldError.

import java.lang.{Exception, Throwable}
class FileError(message: String, reason:Throwable) extends Exception(message, reason)

—

brianhsu@NBGentoo ~ $ scalac -print test.scala 
[[syntax trees at end of cleanup]]// Scala source: test.scala
package <empty> {
  class FileError extends java.lang.Exception with ScalaObject {
    def this(message: java.lang.String, reason: java.lang.Throwable): FileError = {
      FileError.super.this(message, reason);
      ()
    }
  }
}