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Home/ Questions/Q 8169895
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T20:59:39+00:00 2026-06-06T20:59:39+00:00

#include <iostream> #include <string> using namespace std; class A { public: A() { i=1;

  • 0
#include <iostream>
#include <string>

using namespace std;

class A
{
public:
    A() { i=1; j=2;};
    A (A &obj) { i= obj.i+100; j= obj.j+100;};
     int i;
     int j;
};

class B:public A
{
public:
    B():A() {i=10; j=20; k=30;};

    B(A &obj) {  A::A(obj); k=10000; };//

    int k;
};

int main()
{ 
    A dog;
    B mouse(dog);
    cout<<mouse.i<<endl;
    cout<<mouse.k<<endl;

    return 0;
}

I try to write a copy constructor for the derived class that takes advantage of the copy constructor for the base class. I expect that mouse.i should be 101, but in fact the compiling result is 1. The value for mouse.k is 10000, which is expected. I was wondering what’s wrong with my code.

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  1. Editorial Team
    Editorial Team
    2026-06-06T20:59:42+00:00Added an answer on June 6, 2026 at 8:59 pm

    In this constructor:

    B(A &obj) {  A::A(obj); k=10000; };
    

    A::A(obj); does not initialise the base sub-object; instead, it creates a local object also called obj. It’s equivalent to A::A obj;, which is equivalant to A obj;. [UPDATE: or possibly it does something else, or possibly it’s ill-formed – in any event, it’s wrong.]

    You want to use an initialiser list:

    B(A & obj) : A(obj), k(10000) {}
    

    Also, you almost certainly want the constructor parameters to be A const &, to allow construction from constant objects or temporaries.

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