Question

    #include <iostream>
    using namespace std;


    struct InvRec   
        {
        int PartID;
        float Price;
        int Warehouse;
        };

    typedef InvRec *InvRecptr;  
    typedef InvRec arr[];

    typedef InvRecptr * indexarr;

    void deallocate (indexarr & ptrs, int & size)

    {
        for (int i=0; i<size; i++) delete (ptrs[i]);
        delete ptrs;
        ptrs = NULL;
        size = 0;
    };
int getRecordCount();






void main ()
{

    char YN;

    cout << "press a key, at creation";
    cin >> YN;
    InvRecptr *InvRecArray = new InvRecptr[10];

    for (int i = 0; i < 10; i++)
    {
        InvRecArray[i]->PartID = i;

        cout << "\n i = " << i << "\n";
    }
};

the porgram works if the first line in the for loop of main “InvRecArray[i]->PartID = i;
” is commented out but crashes otherwise

Answer 1

The line:

InvRecptr *InvRecArray = new InvRecptr[10];

Allocates an array of pointers. The pointers aren’t allocated themselves, though. Therefore, you need a loop like this to allocate the pointers:

for (int i = 0; i < 10; i++)
{
    InvRecArray[i] = new InvRec;
    // Initialize members of InvRecArray[i]
}