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Home/ Questions/Q 6595571
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:57:25+00:00 2026-05-25T17:57:25+00:00

#include stdafx.h #include<stdio.h> int aarray[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(aarray)/sizeof(int)) int main() { printf(%d\n,SIZE); if(-1<=SIZE)printf(1\n); else

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#include "stdafx.h"
#include<stdio.h>
int aarray[]={1,2,3,4,5,6,7,8};
#define SIZE (sizeof(aarray)/sizeof(int))

int main()
{
    printf("%d\n",SIZE);
    if(-1<=SIZE)printf("1\n");
    else printf("2\n");
    return 0;
}

Why does this prints 2? The SIZE is 8 which is greater than -1 so it should have printed 1. But why is it printing 2? Please help me understand.

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:57:26+00:00Added an answer on May 25, 2026 at 5:57 pm

    You are comparing a signed value (-1) and an unsigned value (the value produced by SIZE is size_t which is unsigned).

    Thus -1 is promoted to an unsigned and becomes larger than SIZE.

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