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Asked: 2026-05-11T11:52:19+00:00

#include <stdio.h> #include <stdlib.h> int main() { FILE *fp = fopen(lr.txt, r); fseek(fp, 0L,

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#include <stdio.h> #include <stdlib.h>  int main()  {      FILE *fp = fopen('lr.txt', 'r');      fseek(fp, 0L, SEEK_END);      int size = ftell(fp);      fseek(fp, 0L, SEEK_SET);       char *lorem_ipsum;       int i = 0;      lorem_ipsum = (char*) malloc(sizeof(char) * size);      while(fscanf(fp, '%s\n', lorem_ipsum) != EOF)      {       printf('%s', lorem_ipsum[i]);       i++;       }      fclose(fp);      return 0; }

This program compiled and ran, however, what happened was that I got a segfault and I don’t know quite exactly what’s wrong with this program. Could somebody help me with the pointer error I got?

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1 Answer

  1. You are trying to print lorem_ipsum[i] as if it were a string. lorem_ipsum is a string, so lorem_ipsum[i] is just a character.

    The segfault happens because printf looks at the value of the character at lorem_ipsum[i] and interprets it as a char* pointer (a string). Naturally, the value of the character doesn’t correspond to a valid, allocated memory address.

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