Question

#include <stdio.h>
#include <string.h>

void func1 (void) { printf( "1\n" ); }
void func0 (void) { printf( "0\n" ); }

typedef struct {
  void (*func0)(void);
  void (*func1)(void);
}mainJT;

static const mainJT coreJT = {
  core_func0,
  core_func1
};

mainJT currJT;

int main()
{
    currJT=coreJT;
    coreJT.core_func0();
    getchar();
    return 0;
}

Please help me fix the errors, I am sure I am making some obvious mistakes. Thanks.

Answer 1

Your question isn’t quite clear but I see what I can find.

typedef struct {
  void (*func0)(void);
  void (*func1)(void);
} mainJT;

Here you are declaring a struct with function pointer members func0 and func1. Then you are trying to define a coreJT variable via an initializer list:

static const mainJT coreJT = {
  core_func0,
  core_func1
};

But this doesn’t work, because there are no functions called core_func0 or core_func1!
Also you try to call

coreJT.core_func0();

which is also incorrect since your struct doesn’t have a member of name core_func0.

---

For a possible solution try renaming your functions like so:

void core_func1 (void) { printf( "1\n" ); }
void core_func0 (void) { printf( "0\n" ); }

and call your function pointer by

coreJT.func0();