#include <stdio.h>
int main()
{
int i = 10;
printf("%d\n", ++(-i)); // <-- Error Here
}
What is wrong with ++(-i)? Please clarify.
#include <stdio.h> int main() { int i = 10; printf(%d\n, ++(-i)); // <– Error
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#include <stdio.h>
int main()
{
int i = 10;
printf("%d\n", ++(-i)); // <-- Error Here
}
What is wrong with ++(-i)? Please clarify.
-igenerates a temporary and you can’t apply++on a temporary(generated as a result of an rvalue expression). Pre increment++requires its operand to be an lvalue,-iisn’t an lvalue so you get the error.