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Editorial Team
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Asked: 2026-05-21T07:45:01+00:00

#include<stdio.h> int main(void) { int a=-3,b=5,c; c=a|b; printf(%d ,c); c=a&b; printf(%d ,c); } The

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#include<stdio.h>

int main(void) 
{
    int a=-3,b=5,c;
    c=a|b;
    printf("%d ",c);
    c=a&b;
    printf("%d ",c);
}

The output is -3 5, please explain how?

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1 Answer

  1. Editorial Team

    Binary of 5 –is–> 0000 0101

    3 --> 0000 0011 — 1's Complement –> 1111 1100 — 2's Complement (add 1) –> 1111 1101 == -3. This is how it gets stored in Memory.

    Bitwise OR Truth Table:

               p OR q

p     ||    q      ||   p | q
T(1)  ||    T(1)   ||     T(1)
T(1)  ||    F(0)   ||     T(1)
F(0)  ||    T(1)   ||     T(1)
F(0)  ||    F(0)   ||     F(0)

    1111 1101 | 0000 0101 = 1111 1101 == -3

    Bitwise AND Truth Table:

              p AND q 

p     ||    q      ||   p & q
T(1)  ||    T(1)   ||     T(1)
T(1)  ||    F(0)   ||     F(0)
F(0)  ||    T(1)   ||     F(0)
F(0)  ||    F(0)   ||     F(0)

    1111 1101 & 0000 0101 = 0000 0101 == 5

    Also, see – What Every Computer Scientist Should Know About Floating-Point Arithmetic.

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