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Home/ Questions/Q 581483
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:35:01+00:00 2026-05-13T14:35:01+00:00

int? x = null; x = x + 1; // Works, but x remains

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int? x = null;
x = x + 1;  // Works, but x remains null

I would expect the compiler to attempt to cast x as an int, but apparently it does not.

Edit by 280Z28: Changed NullReferenceException to InvalidOperationException, which is what Nullable<T>.Value throws when HasValue is false.

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:35:01+00:00Added an answer on May 13, 2026 at 2:35 pm

    This is per the specification for lifted binary operators. From §7.2.7:

    For the binary operators

    + - * / % & | ^ << >>

    a lifted form of an operator exists if the operand and result types are all non-nullable value types. The lifted form is constructed by adding a single ? modifier to each operand and result type. The lifted operator produces a null value if one or both operands are null (an exception being the & and | operators of the bool? type, as described in §7.10.3). Otherwise, the lifted operator unwraps the operands, applies the underlying operator, and wraps the result.

    The reasoning is this: you are to think of null for a nullable type as meaning "I do not know what the value is." What is the result of "I don’t know" plus one? "I don’t know." Thus, the result should be null.

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