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Home/ Questions/Q 6239923
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:28:32+00:00 2026-05-24T11:28:32+00:00

Is there a more efficient/quicker/more sensible to copy part of an ArrayList than the

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Is there a more efficient/quicker/more sensible to copy part of an ArrayList than the way I’m doing it?

 public ArrayList<FooObject> getListOfFlagged() {    
        for(FooObject fooObject: foos) {
            //for each item in the original array, where the item isFlagged...
            if(fooObject.isFlagged) {
                someOtherArray.add(fooObject);
            }
        }    
        return someOtherArray;
    }
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  1. Editorial Team
    Editorial Team
    2026-05-24T11:28:33+00:00Added an answer on May 24, 2026 at 11:28 am

    You can use Collections2.filter() method from guava. It’ll look more functionally:

        Collections2.filter(foos, new Predicate<FooObject>() {
            @Override
            public boolean apply(FooObject input) {
                return fooObject.isFlagged();
            }
        })
    

    The result is backed by your original foos collection, so if you need a copy, then you have to make a defensive copy with new ArrayList<FooObject>(filteredCollection).

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