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Asked: 2026-06-14T17:07:33+00:00

Is there a way to round a python float to x decimals? For example:

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Is there a way to round a python float to x decimals? For example:

>>> x = roundfloat(66.66666666666, 4)
66.6667
>>> x = roundfloat(1.29578293, 6)
1.295783

I’ve found ways to trim/truncate them (66.666666666 –> 66.6666), but not round (66.666666666 –> 66.6667).

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1 Answer

  1. Editorial Team

    Use the built-in function round():

    In [23]: round(66.66666666666,4)
Out[23]: 66.6667

In [24]: round(1.29578293,6)
Out[24]: 1.295783

    help on round():

    round(number[, ndigits]) -> floating point number

    Round a number to a given precision in decimal digits (default 0
    digits). This always returns a floating point number. Precision may
    be negative.

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