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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:10:27+00:00 2026-05-16T14:10:27+00:00

Is there any quick way to, given an executable file, create a Windows service

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Is there any quick way to, given an executable file, create a Windows service that, when started, launches it?

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:10:28+00:00Added an answer on May 16, 2026 at 2:10 pm

    To create a Windows Service from an executable, you can use sc.exe:

    sc.exe create <new_service_name> binPath= "<path_to_the_service_executable>"
    

    You must have quotation marks around the actual exe path, and a space after the binPath=.

    More information on the sc command can be found in Microsoft KB251192.

    Note that it will not work for just any executable: the executable must be a Windows Service (i.e. implement ServiceMain). When registering a non-service executable as a service, you’ll get the following error upon trying to start the service:

    Error 1053: The service did not respond to the start or control request in a timely fashion.

    There are tools that can create a Windows Service from arbitrary, non-service executables, see the other answers for examples of such tools.

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