Question

Is there any way to get the exact address of a function member?
For example I have :

struct foo
{
    void print() { printf("bla bla bla"); }
};
//////////////////////////////////////////////////////////////
unsigned int address = foo::print;

Answer 1

You can use the following syntax to declare the pointer to the member function:

typedef void (foo::*address)();
address func = &foo::print;

In order to call non-static member function you will need an existing instance of that class:

(fooInstance.*func)();