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Home/ Questions/Q 7428295
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T08:43:26+00:00 2026-05-29T08:43:26+00:00

JAXBContext context = JAXBContext .newInstance(CreateExemptionCertificate.class); Marshaller m = context.createMarshaller(); m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); m.marshal(cc, System.out); In

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JAXBContext context = JAXBContext
                    .newInstance(CreateExemptionCertificate.class);
            Marshaller m = context.createMarshaller();
            m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);

            m.marshal(cc, System.out);

In the code above i am getting the result to the console (I mean XML is getting printed on the console). I want to get this XML to a string. I am not getting which argument I should pass to the marshal method to get XML String in a String variable instead of printing it on the console. Anybody having any idea please share.

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  1. Editorial Team
    Editorial Team
    2026-05-29T08:43:27+00:00Added an answer on May 29, 2026 at 8:43 am

    Just now I have got the answer of my question from this post below:

    I want to convert an output stream into String object

    I need to use StringWriter to take XML String from Marshal method

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