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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T09:06:40+00:00 2026-06-12T09:06:40+00:00

Let say I have an array of 1,000,000 elements with about 90% of 0s

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Let say I have an array of 1,000,000 elements with about 90% of 0s and 10% of 1s.

In order to count of 1s, I can do

sum=0;
for(int i=0;i<size;i++) {
    sum+=x[i]
}

But I thought maybe comparison is cheaper than addition so this would be better.

sum=0;
for(int i=0;i<size;i++) {
    if(x[i]==1)
        sum++;
}

But I am not sure. Which one is faster?

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  1. Editorial Team
    Editorial Team
    2026-06-12T09:06:41+00:00Added an answer on June 12, 2026 at 9:06 am

    It is hard to say which one is going to be faster without trying it, but a even a slightly slower instruction without a branch will usually be faster due to pipelining and branch prediction.

    In your case, the branch predictor will be wrong 90% of the time, reducing the speed quite a bit.

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