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Home/ Questions/Q 6116475
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:12:36+00:00 2026-05-23T15:12:36+00:00

let’s say I have a pointer to some base class and I want to

  • 0

let’s say I have a pointer to some base class and I want to create a new instance of this object’s derived class. How can I do this?

class Base
{
    // virtual
};

class Derived : Base
{
    // ...
};


void someFunction(Base *b)
{
    Base *newInstance = new Derived(); // but here I don't know how I can get the Derived class type from *b
}

void test()
{
    Derived *d = new Derived();
    someFunction(d);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:12:37+00:00Added an answer on May 23, 2026 at 3:12 pm

    Cloning

    struct Base {
       virtual Base* clone() { return new Base(*this); }
    };
    
    struct Derived : Base {
       virtual Base* clone() { return new Derived(*this); }
    };
    
    
    void someFunction(Base* b) {
       Base* newInstance = b->clone();
    }
    
    int main() {
       Derived* d = new Derived();
       someFunction(d);
    }
    

    This is a pretty typical pattern.


    Creating new objects

    struct Base {
       virtual Base* create_blank() { return new Base; }
    };
    
    struct Derived : Base {
       virtual Base* create_blank() { return new Derived; }
    };
    
    
    void someFunction(Base* b) {
       Base* newInstance = b->create_blank();
    }
    
    int main() {
       Derived* d = new Derived();
       someFunction(d);
    }
    

    Though I don’t think that this a typical thing to do; it looks to me like a bit of a code smell. Are you sure that you need it?

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